A list of puns related to "Centripetal Acceleration"
Was working on this problem in my classes office hours but wasnβt able to finish it. I showed my work
Theta is an unknown but so is the coefficient of friction. How can I solve for both?
https://imgur.com/a/GEGQUFl
I know what the formula is, but Iβm having trouble grasping what it actually represents. Like, why does it have a magnitude if the magnitude of the velocity is constant when traveling in a circular path? An analogous explanation or an image would be greatly appreciated.
Hey everyone,
I'm having some trouble with the following physics question. Was wondering if anyone could help?
Q: A cylindrical space station has a radius of 57m. The rotation produces artificial gravity equal to 90.0% of the gravity on Earth's surface. (I am assuming then Fg = m(9.8)(0.9) ? )
a) Calculate the centripetal acceleration along the wall of the station.
b) Determine the period of rotation of the station.
If anyone has some pointers on where to start, that would be awesome! Thanks!
Lets say I'm spinning an object on string horizontal to the ground at a substantial speed. The object is experiencing a acceleration towards the center of the string, lets say for the sake of argument 100m/s^2. What I'm confused about is the spinning object is also experiencing a acceleration due to gravity of 9.8m/s^2, so why don't you see the object also accelerate towards the ground as well.
I'm guessing it has to do with the Centripetal acceleration somehow canceling out the gravitational acceleration but I don't understand it mathematically, would anyone be able to explain?
We become dizzy when subjected to centripetal acceleration for example in a playground roundabout. However, linear acceleration does not make us dizzy.
Is the reason we get dizzy from centripetal acceleration due to the acceleration gradient in the radial direction? Or are there other reasons?
Edit: dizziness, not dizzyness :)
Literally the title.
Hello i recently saw here a debate about centripetal acceleration but i don't quite get whats its impact. If let's say car is going to the sharp turn it will maintain it's speed but change direction of velocity which will increase acceleration but i just don't Understand how it changes acceleration if the car maintain it's speed where does that acceleration go like if im going 28m/s and make sharp turn where does all that acceleration go? i have same speed as before and i changed direction. Secondly if let's say a ball on string would keep spinning at the same speed the acceleration would be infinite because it's just keeps and keeps which increases acceleration.
Suppose we have a star and a planet orbiting it. When we want to find the orbital velocity we can equate F=mv^2 / r and F= GMm / r^2. However I found that the centripetal acceleration is not always equal to the gravitational field strength at that point, its always waaaay smaller. Im kind of confused, why can we equate those 2 equations to find orbital velocity when the centripetal acceleration is not equal to gravitational field strength.
I should note that in the course that im doing its pretty basic so we assume circular orbits.
Centripetal acceleration and tangential acceleration are perpendicular. This tells me that they are independent of each other, increasing the magnitude of tangential acceleration should not affect the magnitude of the centripetal acceleration.
My question is that if centripetal acceleration is defined as a=v^2/r, shouldn't the increase in velocity due to the tangential acceleration affect the centripetal acceleration?
A curve of radius 40 m is banked so that a
1090 kg car traveling at 60 km/h can round it
even if the road is so icy that the coefficient of
static friction is approximately zero.
The acceleration of gravity is 9.81 m/s
Find the minimum speed at which a car can
travel around this curve without skidding if
the coefficient of static friction between the
road and the tires is 0.6.
Answer in units of m/s.
First, I solved for v --> v=(sqrt(r(Nsin(theta)-fcos(theta))/m), so now i need to find Nsin(theta) and fcos(theta)
then, i wrote sum of forces without friction and got :
Nsin(theta) = m * (Ac) = 7563
where Ac = v^2/r
Ncos(theta) = mg = 10682
and I know that f=muN, so :
fcos(theta) = mu * Ncos(theta)
Now, i have all the components i need and plug it into my original equation --> v=6.5 m/s
The answer is wrong. what did i miss?
Hi all,
I am working on a question about a car going over some hills and asks me to find where the normal force acting on the car is greatest.
In an explanation it said the normal force is the least when the car is going over a half circle hill because the centripetal acceleration is in the downward direction.
Wouldn't a downward force cause the normal force to increase rather than decrease?
Thanks for the help!
Anything that spins, by definition has a net force acting on it. Because if something is spinning, it's velocity, by definition is changing. So if it is accelerating, by definition there is a net force acting on it.
Alright, so I can understand where this force comes from some examples. If I hold on to a string with a ball and spin it, the force is coming from the tension in the string which is coming from my hand.
But what about when there doesn't appear to be be an external force? For example, I spin a chair. After the initial external force when I spin it, after I let go - the chair still spins. Yet there is no external force acting upon it! So where is the centripetal force acting on it? If there is no force, how is the chair still accelerating? Another example would be a spinning dreidel.
I realize there must be some flaw or oversight in my reasoning, and would be glad to be corrected. Thanks!
Inspired by the latest VSauce video. He explains angular momentum really well, except I felt it missed this specific concept:
Let's say you have a rotating disc D1 and a smaller rotating disc D2 inside of D1. What is the acceleration of a point of D2? Do you have to calculate de centripetal acceleration of both discs and add them or just one of them? https://imgur.com/a/IKDIY0H
A person is swinging a string with washers connected to it that have a mass of 237.8 g how would i find the centripetal force on the string.
I think I know how to do this problem, but just want to confirm.
The question is asking me to find the centripetal acceleration of the moon due to its orbit around earth, using the universal gravity equation Fg=G*me*mm/r^2 (G equals 6.67E-11, me equals mass of the earth, mm equals mass of the moon, r equals distance between the two masses). Basically, what I did was set Fg equal to mm (mass of the moon) times a (its acceleration, the value I'm trying to figure out), and set that equal to the universal gravity equation, which comes out to a=G*me/r^2 (mm being cancelled out). That's what I do, right? (The values for mm, me and r are given in the problem)
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