Do you think it's possible to make chlorine pentafluoride oxide? (ClF5O)? Theoretically, it should be reasonably stable, not to mention a fantastic oxidizer. They made ClF3O and ClF3O2, so I don't see why the pentafluoride variant would be so much harder to manufacture. (that being said, I don't have anywhere near the lab chops and pure guts necessary to make any of the aforementioned substances)
... is the title of my lab. Anyways, hello! I looked over my laboratory notebook for over 5 times and still couldn't figure out these questions, so I'm turning to you guys.
> The reaction of chlorine and aqueous iodine trichloride with NaBr(aq) and NaI(aq) (four separate reactions to consider). State the important observations that support your conclusions
I made a balanced equation (or I think I did) of
- Cl2(aq) + 2NaBr(aq) ↔ 2NaCl(aq) + Br2(aq)
- ICl3(aq) + 3NaBr(aq) ↔ 3NaCl(aq) + IBr3(aq)
- Cl2(aq) + 2NaI(aq) ↔ 2NaCl(aq) + I2(aq)
- ICl3(aq) + 3NaI(aq) ↔ 3NaCl(aq) + 2I2(aq)
I am assuming that the above equations are correct (if they are not, please let me know) but I don't know why or how my observations could support them.
For the first equation, I observed clear colorless solution to clear light yellow solution.
For the second equation, I observed clear colorless solution to clear light yellow solution also.
For the third equation, I observed clear colorless solution to clear, reddish-brown solution.
For the fourth equation, I observed clear colorless solution to clear, light yellow solution (lighter than the second).
> The immediate dissolution and decolouration of leftover iodine in the mortar when treated with 6M NaOH(aq) (third equation I'm referring to is X2(aq)+2)H-(aq) ↔ X-(aq) + XO-(aq) + H2O, where X= Cl, Br, or ).
The lab manual states "In neutral or acidic water, the solubility of the elements follows the trend Br2 >> Cl2 > I2 and the following equilibria apply" X2(g,l,s) <=> X2(aq)
However the solid iodine in this case is reacting with a base, NaOH and therefore wouldn't there be no change made from I2(s) and therefore do not turn into I2(aq)? If we pretend it does happen, how does XO- in the third equation work, because as far as I know there's no such molecule as iodine monoxide.
> The imediate decolouration of leftover ICl3(aq) when treated with 6M HaOH(aq). (Hint: this reaction is best thought of as a sequence of steps which should be written out individually and then combined into an overall balanced chemical equation).
I thought I could use equation number 3 for this but this is not I2(aq), but ICl3(aq). I don't know how to reform the equation so that ICl3(aq) would work in place of X2(aq).
--
Sorry for such a lengthy question and thanks.
Do your worst!
For context I'm a Refuse Driver (Garbage man) & today I was on food waste. After I'd tipped I was checking the wagon for any defects when I spotted a lone pea balanced on the lifts.
I said "hey look, an escaPEA"
No one near me but it didn't half make me laugh for a good hour or so!
Pilot on me!!
Dad jokes are supposed to be jokes you can tell a kid and they will understand it and find it funny.
This sub is mostly just NSFW puns now.
If it needs a NSFW tag it's not a dad joke. There should just be a NSFW puns subreddit for that.
Edit* I'm not replying any longer and turning off notifications but to all those that say "no one cares", there sure are a lot of you arguing about it. Maybe I'm wrong but you people don't need to be rude about it. If you really don't care, don't comment.
What did 0 say to 8 ?
" Nice Belt "
So What did 3 say to 8 ?
" Hey, you two stop making out "
I won't be doing that today!
You take away their little brooms
There hasn't been a post all year!
This morning, my 4 year old daughter.
Daughter: I'm hungry
Me: nerves building, smile widening
Me: Hi hungry, I'm dad.
She had no idea what was going on but I finally did it.
Thank you all for listening.
It’s pronounced “Noel.”
After all his first name is No-vac
What, then, is Chinese rap?
Edit:
Notable mentions from the comments:
-
Spanish/Swedish/Swiss/Serbian hits
-
French/Finnish art
-
Country/Canadian rap
-
Chinese/Country/Canadian rock
-
Turkish/Tunisian/Taiwanese rap
There hasn't been a single post this year!
(Happy 2022 from New Zealand)
Bob
Just to clarify, 12345678
Me grabbing a soda from my (what I thought was) half full 12pk...
Notices there's only 2;
Me: "Awe man... This is a damn bird box!" Her: "What the hell does that mean?!" Me: (Pulls both cans out & shows them to her) "It's only got Toucans."
I'm not ashamed to admit the look on her face was glorious.
I was just sitting there doing nothing.
So that I could frequently say, "I am going to walk 5 miles now."
“BOOM”?!
Because his Visa didn’t work.
"That's what they're fighting about."
"Beauty, because beauty is in the eye of the bee-holder!"
A happy Uncle.....
I’d never seen him be 4.
Ice-olation.
She's only eleven and says she came up with that by herself. I'm so proud 😭😭😭
"No, it doesn't."
We couldn't afford a dog...
You know. Roll reversal.
... is the title of my lab. Anyways, hello! I looked over my laboratory notebook for over 5 times and still couldn't figure out these questions, so I'm turning to you guys.
> The reaction of chlorine and aqueous iodine trichloride with NaBr(aq) and NaI(aq) (four separate reactions to consider). State the important observations that support your conclusions
I made a balanced equation (or I think I did) of
- Cl2(aq) + 2NaBr(aq) ↔ 2NaCl(aq) + Br2(aq)
- ICl3(aq) + 3NaBr(aq) ↔ 3NaCl(aq) + IBr3(aq)
- Cl2(aq) + 2NaI(aq) ↔ 2NaCl(aq) + I2(aq)
- ICl3(aq) + 3NaI(aq) ↔ 3NaCl(aq) + 2I2(aq)
I am assuming that the above equations are correct (if they are not, please let me know) but I don't know why or how my observations could support them.
For the first equation, I observed clear colorless solution to clear light yellow solution.
For the second equation, I observed clear colorless solution to clear light yellow solution also.
For the third equation, I observed clear colorless solution to clear, reddish-brown solution.
For the fourth equation, I observed clear colorless solution to clear, light yellow solution (lighter than the second).
> The immediate dissolution and decolouration of leftover iodine in the mortar when treated with 6M NaOH(aq) (third equation I'm referring to is X2(aq)+2)H-(aq) ↔ X-(aq) + XO-(aq) + H2O, where X= Cl, Br, or ).
The lab manual states "In neutral or acidic water, the solubility of the elements follows the trend Br2 >> Cl2 > I2 and the following equilibria apply" X2(g,l,s) <=> X2(aq)
However the solid iodine in this case is reacting with a base, NaOH and therefore wouldn't there be no change made from I2(s) and therefore do not turn into I2(aq)? If we pretend it does happen, how does XO- in the third equation work, because as far as I know there's no such molecule as iodine monoxide.
> The imediate decolouration of leftover ICl3(aq) when treated with 6M HaOH(aq). (Hint: this reaction is best thought of as a sequence of steps which should be written out individually and then combined into an overall balanced chemical equation).
I thought I could use equation number 3 for this but this is not I2(aq), but ICl3(aq). I don't know how to reform the equation so that ICl3(aq) would work in place of X2(aq).
--
Sorry for such a lengthy question and thanks.
