Torque effect Puns

I personally don't care it it racks up more mileage since I plan on keeping the bike for a while and I got it for cheap but I use the mileage to decide when I do my maintenance. I don't wanna do it to early and definitely don't wanna do it too late. And I don't wanna be speeding accidentally lol.

My brother and I are in a dispute. Torque Tune Gear's effect states that the monster equipped with this card is treated as a tuner. I stated that I could use an xyz monster as a tuner for a synchro monster as long as its equipped with Torque Tune Gear, while my brother states that i can't.

Who's right in this situation?

Hi,

I fly 172 irl and in the sim.

I see when I take off I don't need to use right rudder, almost at all. What I do see is if I fly straight and level in slow speed (172, 55kts, full flaps, ~2000RPM), I do get some indication that I slip to the left, but still, not as much as in real life..

Is there any way to fix it?

Thanks :)

There maybe a better sub to ask this. But I’m asking here anyways.

My wife and I recently inherited a truck from her grandpa, that I’ll eventually use as a daily driver. It’s in pretty good shape, but needs a few things done to it. Namely tires and shocks.

I don’t have much experience working on vehicles so I want to take this opportunity to learn, even if it makes me decide to pay someone to do it fore next go around lol.

Anyways, the shocks seem pretty straightforward (it’s an 01 Silverado 1500) but all the bolts need to re torqued once the new shocks are installed. I’ve never used a torque wrench before.

Would I be ok buying a 3/8” torque and using a reducer for 1/4” sockets, and the same for 1/2” wrench using a reducer for 3/8” sockets? Or would that effect the torque wrench accuracy?

Would like the wheel to correct itself at full force, but want the rest to be dialed down to minimize FFB clipping.

If I have a driver gear (15 teeth) on a motor with 20 N-m, and I have two driven gears coming off of that driver (both 20 teeth) (4:3 ratio), How does this effect the torque on the two driven gears? Is it halved and then multiplied (13.3 N-m on each)? Is it the same across the two driven gears (26.67 N-m on both) ? Thank you!

Title, I just started playing FH 4 and was wondering if those thing effect the overall speed of the car

Hi everyone, I just finished listening to Tom Danielson's latest podcast where he talks about training with power and he went on for a bit about how force application has a bigger effect than just raw power alone. He mentioned that where you apply the power through the pedalstroke has an effect on what comes out of the bike and that he sees it as a factor that separates getting dropped from winning a race. Understandably, he didn't go too far into it as this episode of the podcast seemed like it was advertising for his coaching, but I wanted to know if you guys had any opinions on this. Is this a load of bs or something we should be more conscious of and try to incorporate into our training? If it is something you think about and train, what do you do specifically to build up this specific type of force development/production?

So in school, we're taught that if the wedge is open to the left, ala a PLS or PRI-L/T/M, we will use a counterclockwise torque when we're adjusting in an attempt to "close" the wedge.

My question is: Does torque actually do anything when it comes to addressing the wedge (ie ƟZ misalignment)? I personally cant see how it would have a huge effect, but the Docs on here are way more experience than me so...

D.C.s that have experience with both ways of adjusting (torque and no torque), what are your observations?

ps: I am aware that torque can add speed to the adjustment, but that's not what I'm asking about.

Hello. I am programming a vehicle simulation at the moment and i have trouble combining the torque and the slip ratio.

The longitudinal force a tire creates is a function of the slip ratio. A tire produces the most amount of force at about 0.06 slip ratio. When i apply a torque on a wheel the slip ratio will increase and produce a longitudinal force.

I use the Wikipedia definition of slip ratio. I am aware that this definition is unstable at low speeds and even undefined at velocity of zero but i dont think this is a problem with my question.

Here is my question:
What is the slip ratio if i apply a torque T to the tire?

Here is why i am confused:
My approach is to just accelerate the tire as if there are no other forces. This will increase the angular velocity and now i can calculate the slip ratio. But i dont think this really works. Here is an example.

Here are the relevent values of my tire:
inertia I=1.
radius r=0.5m.
velocity of the axle v=10m/s.
angular velocity omega=20rad/s.
torque T = 1000Nm.

I can apply the torque on the wheel first and then calculate the new slip ratio. If i do this the tire will accelerate by T/I -> 1000/1 -> 1000rad/s/s. So after, for example, one second the new Angular velocity is omega = 1200rad/s!!.

Now my slip ratio is omega*r/v - 1 -> 1200*0.5 / 10 - 1 -> 59.

If i set my timestep to 100ms i get.
omega = 120rad/s.
slip ratio = 5.

if i set m timestep to 10ms i get.
omega = 21rad/s.
slip ratio = 0.05.

I feel like calculating my slip ratio should not be dependent on timestep. At most it should be more precise as the timestep becomes smaller but it should not be linearly dependent on it.

So how can i calculate the slip ratio in a way that is NOT dependent on timestep?

Ive seen a couple posts refering to flywheel size and I don't quite know how it will effect performance. If anyone can link me a page or break it down. For me the knowledge would be much appreciated.

So my question is if we have engine x with a small flywheel does a larger or smaller flywheel generate more torque. And if you are using a multi stage since the second motor doesn't need as much torque and a higher rpm would a larger or smaller flywheel help boost dart speed more?

Ive realised as power increases torque increases because they are a function of each other. But how does more power effect the driving experience vs how does more torque effect the driving experience. And also eli5 the exact difference between power and torque cause at the moment i understand it as power is the rate at wich work is done and torque is the amount of work that can be done.

I've never really felt like I've read a good explanation of the differences that makes it click for me so maybe this question will help.

Lets say a real engine has 300 HP and 300 lbs of torque.

Two new engines are created from that engine design using new technology and wizardry. Both engines have the same internal frictions ect. One engine has 400HP and 300 lbs of torque, the other has 300 HP and 400 lbs of torque.

These two engines are now placed in identical cars. How will each car now behave compared to the other?

I have an object that is rotating with angular velocity ω, and has angular momentum vector L. If there is a torque vector τ affecting to the object for t seconds, how can I determine resulting angular velocity or angular momentum to that object?

The torque vector and angular momentum vector can point to different directions.

I figured I could maybe calculate an angular vector from the torque and add it to the old angular vector L giving me the new angular vector, but I couldn't find any source to confirm this. What would be the correct approach for this problem?

Here's an image that illustrates my painting skills and hopefully also explains the problem: http://i.imgur.com/O2Rv9.png

The background for this question is that I'm programming a simple physics simulator for fun.

edit This was wrong place to post this question after all, but you still helped me to find the answer. Thanks alot darkscout and na85 :-)

Apparently it works the same like force and momentum. So as dp/dt = F works, then following should work: dL/dt = τ, even when the rotation axis differs from the torque axis.

edit2 Or maybe it doesn't work that way.. I'm confused now.

edit3 Thanks Whitw0rth for clarifying things.

http://www.tandfonline.com.ezproxy.lib.rmit.edu.au/doi/abs/10.1080/.U3rOuvmSymc Thankyou in advance!

So recently I realized I needed a torque wrench but all the 3/8 inch drive torque wrenches I see don't have a large enough range for working on cars, they only seem to go to 80 where I would like to have at least up to 150, and all my sockets are 3/8 inch drive. The question I have is this: Can I use a 1/2 inch to 3/8 inch adapter on a torque wrench without effecting the torque being applied, thus allowing me to use a 1/2 inch drive torque wrench with 3/8 inch drive sockets?

So after having used my Assioma duo pedals for quite a long time, I've only recently started looking at the torque effectiveness stats.

I think I understand what it actually measures but I'm not sure to know how to interpret the data. Correct me if I'm wrong, but I believe TE is essentially the percentage of the applied power that propels the pedal forward.

If one does a 300W power output with a TE of 90% resulting in a speed of 15kph (let's assume steep gradient) and then the same 300w effort but with a TE of 100%, ignoring fatigue, does it mean that he will go 10% faster on the second effort ? Or is the physiological cost lower ?

In short, is a higher TE associated with lower physiological cost or actual faster speed ? Is an improved TE going to result in higher power tests ?