Hello, everyone!
As you see in the image below, I want to create an inclined solar panel using the perspective grid tool. However, the angle of elevation is always 0 degree. What should I do to make it looks like an inclined plane that is facing the sun?
https://preview.redd.it/j2iqve43fc281.png?width=3104&format=png&auto=webp&s=b8b298652b4fa48599156f8f76f7cfde727f759b
A jeep should drive up a very steep hill with a slope of 30 degrees. We can assume that the jeep weighs 1500 kg and that the engine efficiency is 30%. b) how large must the coefficient of friction between tire and ground be for the jeep to be able to accelerate by 1.0 m/s^2?
So I tried to split the gravitational force (F_g) into F_x = 1500 * 9.8 * sin 30 and F_y = 1500 * 9.82 * cos 30. Since the jeep has wheels, the friction should be in the direction of motion of the car opposing the rotation of the wheels (am I correct on this one?). So F_f = μ * 1500 * 9.8 * cos 30. Then I tried setting up and equation for the resultant force on the car: F_a + F_f + (-F_x) = 1500 * 1.0 (where F_a is the thrust force making the car accelerate). But I am not sure how to proceed from here, since the equation has two unknowns.
This is what I mean. The force vector of the person rolling the barrel on the incline is less than the person carrying it vertically. I've done tasks like this before and yes, carrying an object to a certain height is easier using an inline than trying to lift it perfectly horizontally.
Why is this the case?
Hello,
This is probably quite simple, but to me its not. I'm just starting out with physics.
The task is to use a small ballpoint pen with a release mechanism on the top, and use it to shoot a marble up an inclined plane.
With only measuring the height difference I should be able to calculate the exit speed of the marble I was told, and to calculate the springforce of the pen. The spring is compressed 0.7 cm before its released.
I created an incline and shot the marble up. It travelled 13 cm. I thought to myself this can be hypotenuse of a 90 degree triangle. I measured the height to be 9.2 cm. I used Pythagoras and the last side of the triangle came to about 9.18 cm. I rounded up to 9.2 to get a triangle with to angles of 45 degrees.
The marble has the mass of 0.005 KG.
Then I thought I could calculate the potential energy the marble has at the top. Which would be mgh = 0.0045 J.
And I wonder, is the spring force equal to the potential energy the marble has at the top? I'm thinking that the spring needs a force of 0.0045 J to push the marble up to the highest point. Is that correct?
When It comes to calculating the exit speed, I'm stuck after figuring out the triangle. Any tips to what I can do?
Edit:
I did the experiment more times with different inclines, and I noticed that the height seems to be almost the same even though the incline changes. Does this mean I can treat it like a shot straight up? So the acceleration becomes that of the gravity? 9.81 m/s^2?
Is thats the case I could use v^2 - v0^2 = 2as to find the velocity?
Hi, this is my first time posting here after lurking for a bit. This is a homework question that I'm absolutely stumped on where to start.
I'm currently taking a college (algebra based) physics course and our lab this week is to take an inclined plane and a friction cart (a little plastic tub). I have to determine the angle needed to put the plane at so the cart slides down at constant velocity. My question is, where would I even start?
I tried taking a video at several different angles and tracking the cart's motion using the Tracker software, and the velocity graphs I'm getting are definitely not constant velocity (a straight line from what I understand).
Should I just put it at a steep angle, take a video, get as close to a straight velocity line as possible, and then say that in real life friction, acceleration, speed, velocity aren't really constants? Or am I completely missing something in this?
any help at all is greatly appreciated! Thanks for your time!
Update: I've gone and worked on this problem and I have another question.
If I find the kinetic friction coefficient (mu k) by using a spring to pull the cart along the plane on a flat surface at a constant rate and recording the force used to pull the cart, I think I can use the equation Force of friction=(mu k) * (Normal force) to solve for the friction.
I'll multiply the mass in kg by gravity to find the normal force.
Will it work if I use the equation Force=(mass) * (acceleration) to relate acceleration to the equation (delta velocity)=(acceleration) * (delta time) ? That way I can relate force, mass, and acceleration to velocity. Also, I need acceleration to be 0 so that the velocity can be constant, correct? .
I then have to relate the angle of the plane to the velocity, acceleration, force of friction, and mass somehow. I have a diagram with all the forces and their directions and labells, and I'm still trying to figure out how to relate the angle to the other things.
Is my line of thought correct, or am I going in the completely wrong direction? How will I relate the angle of the inclined plane to the velocity, acceleration, mass of the friction cart, and the friction?
Hi guys, I have this question here:A 1kg and a 2kg block are released from rest from the top of a 30° inclined plane. The coefficient of kinetic friction is the same for both blocks. Determine the ratio v1/v2, where v1 and v2 are the velocities of the 1kg and 2kg blocks at the base of the inclined plane.
This is my working: https://imgur.com/PC2YHc6
- I derive the equations of the forces acting on both blocks in directions parallel and perpendicular to the surface.
- I derive the equation of the frictional force for both blocks
- I express acceleration in terms of the velocity.
- Replacing the equations in (2) and (3) into (1 - parallel), I get the squared of the final velocity.
- Since both velocities are the same, the ratio is 1.
Is this correct?
Hello! I am taking Physics 12 as a summer course. Genuinely didn't know it would be so hard. I am currently stuck on a lab about inclined planes that deal with forces.
Q: Calculate how much force you would need to apply to the crate to have it move at a constant speed up the 20 degrees ramp. Remember that the crate is now MOVING.
Givens:
mass of crate= 100kg
μk (mu kinetic): 0.3
I understand that NET force must be equalled to 0 since it's constant speed.
