A list of puns related to "Multi Band Excitation"
It seems that full-body saturation sounds almost identical to excitation if the mix is set lower, so it makes me wonder why you might want to omit some parts of a sound. For example, a thunderstorm... the thunder and rain occupy separate parts of the band, but I can't say it sounds better exciting the thunder and rain separately as opposed to saturating everything.
Also, I was wondering how it might be possible to set a "destination band". Say I want to base my excitation off of the 100-250Hz range, but I want the result to only be sent to the 1k-2k range... Is this possible? That would make more sense to me with exciters offering a source AND destination, but seeing as most tend to just be full band for their destination, it feels like their potential is somewhat wasted. You'd think the nature of their bandedness would go both ways.
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I was checking out discography of Poison. Multiple album of 5x-10x platinum. David Bowie, Hall & Oates more albums of course but sold consistently gold. Do album sales tie into how much is spent on promotion and touring? I assume Poison was on tour for years straight. While Bowie/H&O were in the studio.
And hippy type new age bands probably have the record for most instruments played simultaneously by one person.
Jazz bands have the record for being able to meld with each other and play the room.
Itβs weird how certain musical genres can bring out certain types of musical skills in musicians.
Since electricity follows the path of least resistance, would it be possible to solder multiple dipoles resonant to one UHF connector from the feed and ground points? I would assume the RF would go towards the most least resistant dipole antenna, but the radiation pattern would be effected by the other lengths of wire that would also be effecting the SWR because of itβs parasitic characteristics unless itβs only two dipoles facing in different directions.
https://imgur.com/gM96iDC
Almost cant do exalt dungeons or join runs either in fear of bs death or get dc/infini load when enter new area
There is a relationship between eV and Kelvin that is obtained by combining the Boltzmann constant and the elementary charge, from which the relationship 1 eV = roughly 12000 K arises. I read somewhere that this relationship is obtained in the context of electrons velocity distribution in a plasma. But this should apply to everyday situations, right? Like for example in justifying why Cooper pairs are unable to form at room temperature (because the bond energy is like 0.001 eV, which by the relationship above is about 11.6 K). But if a semiconductor has a bandgap of 2 eV, by the same relationship, you should expect that you need to heat it to like 24000 K in order for it to promote electrons to the conduction band. This is obviously not the case.
What am I missing here?
Is there still uncertainty in the location because there isn't an exact location for the excitation? Can you say that you just look for the most energy and say thats the particle?
I have a Fostex A8 and my current mixer doesnβt have tape ins or outs. I just want one mixer for the whole process and donβt want to spend 1k. What mixers you guys using to record your bands?
I am reading an academic paper that talks about compression and I think I understand what the use of multi-band compress is, but I struggle understanding what the filtered side-chain compressors purpose is. It says βIn the case of FSCC, the amount of gain reduction applied to an input signal is influenced by a filtered version of the input signal.β which does not mean anything to me. Would love if someone has a better explanation that is easier to grasp(maybe example as well)!
I am 16yr old student who is studying physics and seeking further information about this topic. It is my understanding that electromagnetic waves can be produced when an electron de-excites, it loses energy which is emitted as light. However, I read online that electromagnetic radiation is caused by a disturbance in electric field which causes a disturbance in the perpendicular magnetic field etc.
If this is the case then why doesn't excitation cause a photon to be emitted? The electron is moving to an excited state, wouldn't this cause a disturbance in the electric field? However, when the electron is excited, it gains energy so I don't think it would emit a photon.
I am probably misunderstanding these concepts and I would appreciate any explanation. Thank you
(sorry in advance for length haha) I recorded a (rushed) acoustic/folk album this summer before returning to college, with the intent of mixing and producing it during school. However, as Iβve been mixing (by the way Iβm a complete and utter novice; this is my first time mixingβif you can call what Iβm doing mixing lol) Iβve noticed that some of my stereo guitar recordings have noise. As in, a lot of noise. In hindsight, itβs probably due to the micβ>XLRβ>INSTβ>interface setup I had to use for 1/2 of every stereo mic setup (this was all I could manage. #broke).
Iβve been tearing my hair out trying to get rid of the noise. If it was even across the stereo image it would actually be better; having noise in my left ear only is terrible. Iβve tried EQing it out but the noise is audible from like ~7k and higher. Ideally Iβd re-record but thatβs not an option.
BUT!! I just began messing around with a multi band compressor. For kicks. And whaddya know, it automatically lowers the higher frequencies when the guitar kicks out, so the noise dissipates during quieter moments, at least.
Now Iβm pretty sure multiband compressors are a mastering tool. Does it make sense to use them this early in the production process? Is there a better way to eliminate noise across a broad frequency range without killing the main shimmer/sparkle of the guitar?
Again, I say this knowing that re-recording is the best option.
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