Efficiency ratio Puns

Where I live 1080ti cards go for 400-500 and 1080s go for 400ish. Anyone have any better recommendations?

Have to wait...

Since thermal efficiency is net work out / heat in.

For the entire efficiency of a two shaft, it is the work out of the Low Pressure power turbine while the heat energy in is the combustion of the fuel??

How can I compare it to the pressure ratio (of the compressor)

why is propeller efficiency low at both high advance ratio and low advance ratio, I suspect RPM and velocity cause that but I am not sure how to fully comprehend

eff vs adv ratio

My '99 accord Is low on compression, in one cylinder. The F23A1 (2.3 4cyl) that's in it shares the same bore, and wrist pin size&location as any K20, and it's a common swap with the frankenstein engine guys (usually paired with an H22 head for DOHC). After doing the math, there are no common done/dish sizes for K20 piston sets that exactly match the F23's compression ratio, and I was wondering if an increase or decrease in base ratio, or piston shape would change VE at all.

Cylinder head is new reman, less than 5k miles, valves are adjusted properly. It was replaced because of a chipped exhaust valve. It has low comp on the same cylinder as the bad valve leading me to believe the piston ring grooves aren't perfect.

I plan on turbocharging the engine in the future, I already have head studs, the piston heads are the only thing that needs upgrading before I can add 10lbs for the long term, and drive it for at least another 50k.

The reason I'm trying to avoid a change in VE is so that I can still drive the car without issue on the stock speed density computer.

Because i couldn't find any hint to that, i made it by myself.A three layer solution for early T1 game 3to4 ratio production (mostly cement)

In wich you have feed rates of 45 and output of 15

Feed in 3x60 output 1x60, all T1, no mods

Feed 3x60 from mid bottom split into 6x30

input: 3 mid bottom

output: 1 mid left, 2 left and right corner top, 1 mid right, 2 left and right bottom corner

---

6x30 split into 12x15,

input: 1 mid left, 2 mid top, 1 mid right, 2 mid bottom.

output: 4 Left top and bottom corner, 2 mid top, 4 right top and bottom corner, 2 mid bottom.

---

Merging 3x15 into 1x45

input: 4 Left top and bottom corner, 2 mid top, 4 right top and bottom corner, 2 mid bottom.

output: 2 left and right top corner, 2 left and right bottom corner.

So I looked on the wiki about the ratio of the science packs and with the use of the Kirk McDonald calculator I was able to figure out the ratio of white science as well. It started with the fact that I wanted to see what you would need to have 0 waste in the entire production as in nothing is waiting on anything, there is no unused belt space, every pipe has exactly what is needed, etc. This is under the assumption that you have 0 mining research and use Assembler 3's with no modules or beacons.

So the ratio I found was

To put it more nicely...

If you can support this many factories then you will have the exact output of science per minute, but what if you don't want to waste anything? Well, I worked through a bunch of numbers and found that if you want to maintain exact 1:1 with everything without 0 waste, then take a look here and this was after reducing it as much as I could. This does not take into account your uranium production or any side productions. So if your factory can support about 12.85 PW then you can achieve perfection!

Example;

Say I wish to achieve 100% efficiency constructing iron plates. The recipe for iron plates in a constructor are ---

3 iron ingots will output 2 iron plates per 6 seconds (or) 30 iron ingots will output 20 iron plates per minute.

So all I would need to do is ensure that exactly 30 iron ingots reach that constructor per minute right? Is that all there is too it, matching input capacities so constructors, assemblers, etc. do not freeze up?

I thought it would be that simple, but I am still somehow ending up with stacks of ingots in constructors, diminishing efficiency.

Is there something else I have not taken into account?

I've read 'enough screen gives CV +10% sortie efficiency' on wiki.

And they never told me, how much I need.

I know I need at least 1 Battleline-ship(capital ship with guns) for 1 CV, and 3 screens (light ships) for 1 capital ship, for perfect torpedo and heavy gun block to the CV.

so what I need at least is: 4 CVs, 4 BBs, 24 Screens. I might need more than 24 screens, because screen ships die easily.

But for that +10% sortie efficiency...? Do I need more? Or is it achieved with just 100% screen efficiency?

I'm on my second base, would very much classify myself as a new player though, and I'm a little confused about ratios and factory design.

I'm setting up my electronic circuit assemblers, and thought the ratio was 2 green circuit assemblers for every 3 copper wire assemblers, so I built 12 copper wire for 8 green circuit assemblers (screenshots attached).

Anyway, when I started the assemblers up, there was not enough copper wire being produced to reach the last two circuit assemblers, you can see this in the screenshot. I know they will eventually reach the last two assemblers as the circuit belts are filled but this seems inefficient to me, or am I just misunderstanding something? I tried to get it so the copper wire would have four output belts each feeding two circuit assemblers, however I couldn't come up with a factory design that'd make that possible.

So basically, am I misunderstanding ratios? Is this design actually inefficient or is it not really a big deal?

This may be common knowledge, but I want to share with you guys my revelation that I came across while answering another post. Hopefully it is helpful to someone out there besides me.

The person had a biomass constructor feeding a biofuel constructor and was wondering why it was inefficient. I figured out that, at 30 leaves/min, the machines were running at 20% and 30% efficiency respectively. On the drive home from work I started to think that those percentages seemed familiar. In fact, the ratio is 2:3 for biomass machines to biofuel machines. I.E. For every 2 biomass machines (@90 biomass output each), you need 3 biofuel machines (@60 biomass input each) to stay 100% efficient).

I realized then that the ratios isn't just for the number of machines, but obviously for the over/under-clocking as well, since if you under-clocked those machines to those specific percentages (again respectively), the efficiency would go to 100%. So, in reality, it isn't for every 2 you need 3, it is for every 2% you need 3%.

40% : 60% would work

80% : 120% would work

180% : 270% would work

Discovering this, I wanted to tackle something a bit more complex - Computers...

Using only base recipes, computers need (in units/min):

Circuit Boards (CB's) - 9.375

Cable - 22.5

Plastic - 33.75

Screw - 112.5

The output of those required machines are as follows (in units/min):

CB's - 5

Cable - 15

Plastic - 22.5

Screw - 90

Doing some math, and making everything a whole number, here are the ratios (for every number of these machines : you need this many computer manufacturers):

CB's - 15 : 8

Cable - 3 : 2

Plastic - 9 : 6

Screw - 5 : 4

Again we are basing everything off the requirements of computers, so the right hand side of each ratio. Again, doing some math, the least common multiple between all is 24 (8 x 3, 2 x 12, 6 x 4)... here are the new adjusted ratios

CB's - 45 : 24

Cable - 36 : 24

Plastic - 36 : 24

Screw - 30 : 24

So what does that mean? Well, in order to run 24 non-over/under-clocked manufactures producing computers you need that many structures producing everything else. OR for every 24% of computers you do, you need that many percentages of everything else to stay at 100% efficiency. So, using one machine of everything, without over-clocking, here is the max you can do (since clock percentages aren't floatable):

CB's - 90% : 48%

Cable - 72%

Hi guys! So I'm REALLY having a hard time with these several problems in my algebra review materials. Word problems are not really my forte. I need some tips or guides in dealing with these type of problems.

Here is a sample problem: A piece of work can be done by women in 11 days and 30 men in 7 days. In how many days can the work be done by 22 women and 21 men?

The answer to this question is 5. But I dont really know how to solve it.

Now, I know that you'll use ratio and proportion in this problem. The problem is, the number of women in the first sentence is not indicated and proportionality could not be done with the number of working men. Am I right?

Hope you could help me! Thanks!

Like in this case, for example: Ketamine was considered effective because 55% experienced a reduction in the SSI score vs. 30% in the placebo group, hence an impressive OR of 2.85. But is this really enough? Half experiencing half less suicidal thoughts doesn't seem like a great deal to me, especially when 1/3 also experienced the same taking midazolam...

https://www.medscape.com/viewarticle/890011

noob here, and i kind of want to fact check what I'm looking at and ensure that I am comprehending these gearing ratios correctly.

Below is a comparison of the Bike ratio I currently have (left), and the one I am looking to switch to (right).

Im essentially looking to see if i would be gaining granny gears or losing granny gears, and how my top level speed is affected.

It appears that I m actually gaining some granny gears that would make it easier to climb, and losing some high end higher speeds gears?

Can someone explain to me if this is correct? and if not then what the differences are?

Thanks!

https://imgur.com/3mOs4Yw

Is there no sort of penalty for carrying around all that non-coding DNA?